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Can any one help me out in finding last 3 digits of 1233^101. thanks

(1233)101

(1233)101 = (1233)100 x 1233 The last three digits of the above ll depend only on 233 not anything left to that. 

power                  last 3 digits
12332            289

12333             337

12334             521 

12335             393

12336             569

12337             577

12338             441

12339             753

123310            449
Now we know 10th power of 449 is 001 ie last 3 digit of 44910 is 001 So the last 3 digit of (1233)100 = the last 3 digit of (449)10 10 = So the last 3 digit of (001)10 = 001 Thus the last 3 digits are 233